Categories Here’s a little basic physics lesson that should prove extremely useful when working on your amps. When you add resistors and capacitors in series or parallel, the total values you end up with can be worked out with simple formulae.

When you add capacitors in parallel (i.e. connected together twice, at both ends), the new value you end up with is simply the value of the first capacitor plus the value of the second capacitor. For example, a pair of 250pf capacitors in parallel would give a value of 500pf. A 500pf and a 250pf capacitor in parallel would give a working value of 750pf.

Therefore it’s fair to say that C1 + C2 = Ct, where C1 is the first capacitor’s value, C2 the second’s, and Ct is the resulting capacitance value.

Here’s where it gets a little harder to work out. In series (i.e. connected one after another), the resulting capacitance is found by this formula:

1 + 1 1 +   ….  = 1
C1     C2      C3                 Ct

so you work out the total capacitance by using fractions. Let’s try this with the examples above (250pf and 250pf, 500pf and 750pf):

1 + 1 = 1
250    250     125

1 + 1 = 1
500    750       300

Therefore a pair of 250pf caps in series gives you 125pf capacitance, and a 500pf then 750pf capacitor in series would give you 300pf in capacitance.

Now that you’ve learnt how to add capacitor values, you can easily do it now with resistors – it’s just the same but backwards. You use the same formula for adding resistors in parallel as you would for adding capacitors in series, and you also use the same formula for adding resistors in series as you would for adding capacitors in parallel.

Therefore, the total resistance when adding resistors in parallel is simply:

1 + 1 1 +   ….  = 1
R1      R2      R3                Rt

where R1, R2, R3 etc is the first resistor, second resistor, third resistor etc, and Rt is the total resistance gained.  